GATE Question of The Day - Digital Electronics Questions

Hi dear GATE aspirants! I am SouravMani.From today we are going to discuss Digital Electronics Questions on daily basis. hope you all co-operate and making use of it.

The logic functions implemented by the circuit below is (Ground implies a logic "0")





A) F = AND(P,Q)
B) F = OR(P,Q)
C) F = XNOR(P,Q)
D) F = XOR(P,Q)


I kindly requesting of the GATE aspirants to justify yours valuable Answers.

16 comments:

  1. Can you please justify above..

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  2. haah... its D for sure.... good question dude... but a little bit easy right...

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  3. ya people are asking easy question also, but you dont worry we have some very tough question for you. he he

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  4. hoh man... i didn't mean that...actually every one can solve easy questions right if they know the concepts perfectly... but i am telling you that whether the question is easy or tough but it should be some what tricky and thinkable dude...i am telling you that only...

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  5. vamshi here i left some of the part for you http://www.gate.examsavvy.com/2012/08/gate-question-of-day-general-aptitude_30.html

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  6. D
    damn easy.. :)
    but stil a gud one..

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  7. Dont worry dude's always begin with a easy ones from which you get confidence to go ahead!

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  8. Off course many aspirants have done their suggestions/justifications well. yes guys you are obsolutely correct! The answer is option D. well done friends*

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  9. option D
    I0 fed with logic 0
    I1 fed with logic 1
    I2 fed with logic 1
    I3 fed with logic 0
    Hence in order to select I1 or I2 we can have combinations either Q=0 P=1 for I1 and Q=1 P=0 for I2. So we can represent this easily by XOR between P and Q. Hence F=XOR(P,Q). :)

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