Hi dear GATE aspirants! I am SouravMani.From today we are going to discuss Digital Electronics Questions on daily basis. hope you all co-operate and making use of it.
The logic functions implemented by the circuit below is (Ground implies a logic "0")
A) F = AND(P,Q)
B) F = OR(P,Q)
C) F = XNOR(P,Q)
D) F = XOR(P,Q)
I kindly requesting of the GATE aspirants to justify yours valuable Answers.
The logic functions implemented by the circuit below is (Ground implies a logic "0")
A) F = AND(P,Q)
B) F = OR(P,Q)
C) F = XNOR(P,Q)
D) F = XOR(P,Q)
I kindly requesting of the GATE aspirants to justify yours valuable Answers.
Posts
16 comments:
D is the ans
Can you please justify above..
haah... its D for sure.... good question dude... but a little bit easy right...
ya people are asking easy question also, but you dont worry we have some very tough question for you. he he
option D
hoh man... i didn't mean that...actually every one can solve easy questions right if they know the concepts perfectly... but i am telling you that whether the question is easy or tough but it should be some what tricky and thinkable dude...i am telling you that only...
hmm ok
vamshi here i left some of the part for you http://www.gate.examsavvy.com/2012/08/gate-question-of-day-general-aptitude_30.html
D
damn easy.. :)
but stil a gud one..
Dont worry dude's always begin with a easy ones from which you get confidence to go ahead!
hmm gud suggestion dude...
D is the answer
Off course many aspirants have done their suggestions/justifications well. yes guys you are obsolutely correct! The answer is option D. well done friends*
option D
I0 fed with logic 0
I1 fed with logic 1
I2 fed with logic 1
I3 fed with logic 0
Hence in order to select I1 or I2 we can have combinations either Q=0 P=1 for I1 and Q=1 P=0 for I2. So we can represent this easily by XOR between P and Q. Hence F=XOR(P,Q). :)
damn easy....:P
D is d ans.
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