Graduate Aptitude Test in EngineeringGATE 2013 Exam, Syllabus, Coaching, Study materials, GATE Question Papers and GATE Preparation Books |
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19 comments:
ans a
ans a
a
A
ans.a
i hope many aspirants do have the same confidence level. yes you are correct friends. its "A" the answer.
'A '
c
Ans A
From the first mux output Y=A Xor B and the second MUX output is X=YXorC. Substitute Y in X.
=> X=A Xor B Xor C .
plzz answer with explanation...
option D
a
ans c
y=A'B'(0)+ AB'(1)+A'B(1)+AB(0)
=A'B+AB'
Now
x=(A'B+AB')'C'(0)+(A'B+AB')C'(1)+ (A'B+AB')'C(1)+ (A'B+AB')C(0)
= (A'B+AB')C'+ (A'B+AB')'C
=A'BC'+AB'C'+A'B'C+ABC
=ANSwer
a
a
A
A
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