There are two candidates P and Q in an election. During the campaign 40% of the voters promised to vote for P, and rest for Q. However, on the day of election !5% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose, P lost by 2 votes, then what was the total number of voters?
A) 100
B) 110
C) 90
D) 95
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50. This question is remain active for 5 days. last day to answer is 10/09/12. All the best.
50. This question is remain active for 5 days. last day to answer is 10/09/12. All the best. 
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7 comments:
Let the number of voters = x.
the number of candidates which promised to vote for P = .4x
the no. of candidates promised to vote for Q = x-.4x=.6x
According to given condition,
15% of .4x voters went back on their promise to vote for P and instead voted for Q.
so:
.4x * 15/100=.06x
25% of 60 voters went back on their promise to vote for Q and instead voted for P.
so:
.6x * 25/100=.15x
the total no. of votes for P = .4x–.06x+.15x= .49x
so as the total no. of Votes for Q =.6x+.06 – .15x = .51x
Difference of Votes = .51x – .49x = 2
.02x=2
x=2/.02
x=100
so there will be hundred voters
Also P lost by 2 Votes.
⇒ Number of Voters were 100
Option is A.
Let the question be solved in this way, supposing the total number of voters in village be x.
As 40% promised for P but only 25% turned back , for Q they promised 60% but only 35% votes are polled for him and remaining 25% for P.
So, P=25+25, Q=15+35
Now , the count is 50% each and now let X be the percentage of votes after poll, as per analogy X+X+2=100% or X=49% and other won by 51% out of 100% which means 100 votes polled.
A only
it is option A 100
answer:a
@ Manoj and Karthik Reddy (Winner rs 50 mobile recharge free)
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a is the answer
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